The objective and the eyepiece of a microscop | vedclass

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(C) The total magnification $m$ of a compound microscope is given by the product of the magnification of the objective lens $(m_o)$ and the magnificat

Vedclass · Accepted Answer

$300$

Vedclass · Answer

(C) The total magnification $m$ of a compound microscope is given by the product of the magnification of the objective lens $(m_o)$ and the magnification of the eyepiece $(m_e)$: $m = m_o 	imes m_e$.Given,the magnification of the objective $m_o = 30$.When the final image is viewed at infinity,the magnification of the eyepiece is given by $m_e = \frac{D}{f_e}$,where $D$ is the least distance of distinct vision $(25 \, cm = 250 \, mm)$ and $f_e$ is the focal length of the eyepiece $(25 \, mm)$.Substituting the values: $m_e = \frac{250 \, mm}{25 \, mm} = 10$.Therefore,the total magnification $m = 30 	imes 10 = 300$.

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